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Sunday, September 29, 2024

Donald J. Trump won Bloomingburg precinct with 63.2 percent of the vote in 2016

Vote 15

Donald J. Trump won the Bloomingburg precinct with 63.2 percent of the vote in the 2016 election, a margin of 85 votes.

In 2016, 62.6 percent of all registered voters in the precinct, 261 total voters, voted in the Presidential race. Of those who voted, Donald J. Trump received 63.2 percent of the total vote in the precinct and 51.8 percent in the state overall. Recent registration data shows there has been little change in registration data with a total registered of 415. If the parties received the same percentage of the vote in 2020, Donald J. Trump would win by a margin of 85 votes.

"I expect voter turnout to be exceptional, perhaps the highest in over a century, since 1908," said Michael McDonald, who directs the U.S. Elections Project. If those estimates are correct and we get the same 65.7 percent participation that there was then, the voter turnout in the country would jump from 133 million up to 145 million people, according to the Brookings Institute.

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